(x-1)(x^2+x+2)=0

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Solution for (x-1)(x^2+x+2)=0 equation: 


Simplifying
(x + -1)(x2 + x + 2) = 0

Reorder the terms:
(-1 + x)(x2 + x + 2) = 0

Reorder the terms:
(-1 + x)(2 + x + x2) = 0

Multiply (-1 + x) * (2 + x + x2)
(-1(2 + x + x2) + x(2 + x + x2)) = 0
((2 * -1 + x * -1 + x2 * -1) + x(2 + x + x2)) = 0
((-2 + -1x + -1x2) + x(2 + x + x2)) = 0
(-2 + -1x + -1x2 + (2 * x + x * x + x2 * x)) = 0
(-2 + -1x + -1x2 + (2x + x2 + x3)) = 0

Reorder the terms:
(-2 + -1x + 2x + -1x2 + x2 + x3) = 0

Combine like terms: -1x + 2x = 1x
(-2 + 1x + -1x2 + x2 + x3) = 0

Combine like terms: -1x2 + x2 = 0
(-2 + 1x + 0 + x3) = 0
(-2 + 1x + x3) = 0

Solving
-2 + 1x + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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